If meena gives an interest of Rs 45 for one year at 9% rate p.a. what is the sum she has borrowed?
Answers
Answered by
32
s.i.=p×r×t/100
45=p×9×1/100
RS 500(principle)
45=p×9×1/100
RS 500(principle)
Answered by
50
GIVEN => Simple interest = rs 45
=> Rate of interest = 9 % pa
=> Time = 1 year
Solution => SI =![\frac{P \: × \: R \: × \: T}{100} \frac{P \: × \: R \: × \: T}{100}](https://tex.z-dn.net/?f=%5Cfrac%7BP+%5C%3A+%C3%97+%5C%3A+R+%5C%3A+%C3%97+%5C%3A+T%7D%7B100%7D)
=> 45 =![\frac{P \: × \: 9 \: × \: 1}{100} \frac{P \: × \: 9 \: × \: 1}{100}](https://tex.z-dn.net/?f=%5Cfrac%7BP+%5C%3A+%C3%97+%5C%3A+9+%5C%3A+%C3%97+%5C%3A+1%7D%7B100%7D)
=> P =![\frac{45×100}{9} \frac{45×100}{9}](https://tex.z-dn.net/?f=%5Cfrac%7B45%C3%97100%7D%7B9%7D)
=> P =![\frac{4500}{9} \frac{4500}{9}](https://tex.z-dn.net/?f=%5Cfrac%7B4500%7D%7B9%7D)
=> P = 500
Principal = Rs 500
=> Rate of interest = 9 % pa
=> Time = 1 year
Solution => SI =
=> 45 =
=> P =
=> P =
=> P = 500
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