Question

If meena gives Rs45 for one year at 9% rate p.a..What is the sum she has borrowed.

Answer 1

hey mate...

$p = 45.r = 9\%..t = 1 \\ si = ptr \div 100 \\ si = (45 \times 9 \times 1) \div 100 \\ si = 81 \div 20 \\ si = 4.05 \\ \\ \\ \\ now \: sum = 45 + 4.05 = 49.05rps \\ i \: hope \: u \: got \: this$

Answer 2

The sum borrowed is Rs.500.

Step-by-step explanation:

Given : If Meena gives an interest of Rs.45 for one year at 9% rate p.a.

To find : What is the sum she has borrowed ?

Solution :

Applying interest formula,

I= P*T*R

Where, I=Rs.45 is the interest

R=9%=0.09 is the interest rate

T=1 year is the time

P is the principal or sum

Substitute the value in the formula,

45 = p*0.09*1

P= 45/0.09

P= 500

Therefore, The sum borrowed is Rs.500.