If memory access takes 20 ns with cache and 110 ns without it, then the ratio ( cache uses a 10 ns memory) is
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the ratio (cache uses a 10 ns memory) is 0.9
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Cache memory :
Explanation:
- Cache memory is a hardware or software component that stores data so that future requests for data can be served faster.
- This data stored in a cache may be the result of an earlier computation or a copy of data stored elsewhere.
The cache memory is calculated by a formula
C = Hit% × ( cache time ) + ( 1 - h ) × ( cache + main memory )
In this problem,
cache time= 10ns
memory access time with cache =20ns
main memory time=110ns
Put this in above equation
20 = h (10) + (1-h) (110)
Solving above equation we get
h = 0.9
Then the required ratio is calculated by
0.9 × 100 = 90%
The required ratio is 90%.
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