If metals 'X' and 'Y' do not react with water at all, then X and Y cannot be
Answers
Gold does not react with water as it is present below hydrogen in the metal activity series. The metals which are placed below the hydrogen in the metal activity series can not displace hydrogen ion.
refer the attachment
X is sodium, Y is magnesium and Z is iron.
X is sodium, Y is magnesium and Z is iron. 2Na+2H
X is sodium, Y is magnesium and Z is iron. 2Na+2H 2
X is sodium, Y is magnesium and Z is iron. 2Na+2H 2
X is sodium, Y is magnesium and Z is iron. 2Na+2H 2 O→2NaOH+H
X is sodium, Y is magnesium and Z is iron. 2Na+2H 2 O→2NaOH+H 2
X is sodium, Y is magnesium and Z is iron. 2Na+2H 2 O→2NaOH+H 2
X is sodium, Y is magnesium and Z is iron. 2Na+2H 2 O→2NaOH+H 2
X is sodium, Y is magnesium and Z is iron. 2Na+2H 2 O→2NaOH+H 2 Mg+2H
X is sodium, Y is magnesium and Z is iron. 2Na+2H 2 O→2NaOH+H 2 Mg+2H 2
X is sodium, Y is magnesium and Z is iron. 2Na+2H 2 O→2NaOH+H 2 Mg+2H 2
X is sodium, Y is magnesium and Z is iron. 2Na+2H 2 O→2NaOH+H 2 Mg+2H 2 O→Mg(OH)
X is sodium, Y is magnesium and Z is iron. 2Na+2H 2 O→2NaOH+H 2 Mg+2H 2 O→Mg(OH) 2
X is sodium, Y is magnesium and Z is iron. 2Na+2H 2 O→2NaOH+H 2 Mg+2H 2 O→Mg(OH) 2
X is sodium, Y is magnesium and Z is iron. 2Na+2H 2 O→2NaOH+H 2 Mg+2H 2 O→Mg(OH) 2 +H
X is sodium, Y is magnesium and Z is iron. 2Na+2H 2 O→2NaOH+H 2 Mg+2H 2 O→Mg(OH) 2 +H 2
X is sodium, Y is magnesium and Z is iron. 2Na+2H 2 O→2NaOH+H 2 Mg+2H 2 O→Mg(OH) 2 +H 2
X is sodium, Y is magnesium and Z is iron. 2Na+2H 2 O→2NaOH+H 2 Mg+2H 2 O→Mg(OH) 2 +H 2
X is sodium, Y is magnesium and Z is iron. 2Na+2H 2 O→2NaOH+H 2 Mg+2H 2 O→Mg(OH) 2 +H 2 3Fe+4H
X is sodium, Y is magnesium and Z is iron. 2Na+2H 2 O→2NaOH+H 2 Mg+2H 2 O→Mg(OH) 2 +H 2 3Fe+4H 2
X is sodium, Y is magnesium and Z is iron. 2Na+2H 2 O→2NaOH+H 2 Mg+2H 2 O→Mg(OH) 2 +H 2 3Fe+4H 2
X is sodium, Y is magnesium and Z is iron. 2Na+2H 2 O→2NaOH+H 2 Mg+2H 2 O→Mg(OH) 2 +H 2 3Fe+4H 2 O→Fe
X is sodium, Y is magnesium and Z is iron. 2Na+2H 2 O→2NaOH+H 2 Mg+2H 2 O→Mg(OH) 2 +H 2 3Fe+4H 2 O→Fe 3
X is sodium, Y is magnesium and Z is iron. 2Na+2H 2 O→2NaOH+H 2 Mg+2H 2 O→Mg(OH) 2 +H 2 3Fe+4H 2 O→Fe 3
X is sodium, Y is magnesium and Z is iron. 2Na+2H 2 O→2NaOH+H 2 Mg+2H 2 O→Mg(OH) 2 +H 2 3Fe+4H 2 O→Fe 3 O
X is sodium, Y is magnesium and Z is iron. 2Na+2H 2 O→2NaOH+H 2 Mg+2H 2 O→Mg(OH) 2 +H 2 3Fe+4H 2 O→Fe 3 O 4
X is sodium, Y is magnesium and Z is iron. 2Na+2H 2 O→2NaOH+H 2 Mg+2H 2 O→Mg(OH) 2 +H 2 3Fe+4H 2 O→Fe 3 O 4
X is sodium, Y is magnesium and Z is iron. 2Na+2H 2 O→2NaOH+H 2 Mg+2H 2 O→Mg(OH) 2 +H 2 3Fe+4H 2 O→Fe 3 O 4 +4H
X is sodium, Y is magnesium and Z is iron. 2Na+2H 2 O→2NaOH+H 2 Mg+2H 2 O→Mg(OH) 2 +H 2 3Fe+4H 2 O→Fe 3 O 4 +4H 2
X is sodium, Y is magnesium and Z is iron. 2Na+2H 2 O→2NaOH+H 2 Mg+2H 2 O→Mg(OH) 2 +H 2 3Fe+4H 2 O→Fe 3 O 4 +4H 2
X is sodium, Y is magnesium and Z is iron. 2Na+2H 2 O→2NaOH+H 2 Mg+2H 2 O→Mg(OH) 2 +H 2 3Fe+4H 2 O→Fe 3 O 4 +4H 2
X is sodium, Y is magnesium and Z is iron. 2Na+2H 2 O→2NaOH+H 2 Mg+2H 2 O→Mg(OH) 2 +H 2 3Fe+4H 2 O→Fe 3 O 4 +4H 2 Their sequence in reactivity series is as follows:
X is sodium, Y is magnesium and Z is iron. 2Na+2H 2 O→2NaOH+H 2 Mg+2H 2 O→Mg(OH) 2 +H 2 3Fe+4H 2 O→Fe 3 O 4 +4H 2 Their sequence in reactivity series is as follows: Fe<Mg<Na