Question

if mid point of (2,x) and (_3,2)is (1/2,5) find x​

Answer 1

Step-by-step explanation:

$\frac{x + 2}{2} = 5 \\ x =10 - 2 \\ = 8 \\ thus \: x \: here \: is \: 8$

Answer 2

Step-by-step explanation:

Given :-

Mid point of (2,x) and (-3,2) is (-1/2,5)

Correction :-

Mid point = (-1/2,5)

To find :-

Find the value of x ?

Solution :-

Given points are (2,x) and (-3,2)

Let (x1, y1) = (2,x) => x1 = 2 and y1 = x

Let (x2, y2) = (-3,2) => x2 = -3 and y2 = 2

We know that

The coordinates of the mid point M(x,y) of a linesegment joining the points (x1, y1) and (x2, y2) is ({x1+x2}/2, {y1+y2}/2)

On Substituting these values in the above formula then

=> M(x,y) = ( {2-3}/2 , { x+2}/2 )

=> M(x,y) = ( -1/2 , (x+2)/2 )

According to the given problem

The mid point = (-1/2 , 5)

=> ( -1/2 , (x+2)/2 ) = (-1/2 , 5)

On Comparing both sides then

=> (x+2)/2 = 5

=> (x+2) = 5×2

=> x+2 = 10

=> x = 10-2

=> x = 8

Therefore, x = 8

Answer:-

The value of x for the given problem is 8

Used formulae:-

→ The coordinates of the mid point M(x,y) of a linesegment joining the points (x1, y1) and (x2, y2) is ({x1+x2}/2, {y1+y2}/2)