if min hand is 12 m long.then area swept by it in 35 degrees
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Given;
- r = 12m
- θ = 35°
Thus area of sector ;
= πr²× θ/360°
- 22/7 × 12 × 12 × 35/360
- 22 × 12 × 12 × 5/360
- 22 × 144 × 1/72
- 22/72 × 144
- 1/6 × 144
- 24 m²
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