if minus 3 is a zero of a polynomial x cube + 3 X square + 20 X + k then find the value of k
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x = - 3
p ( x ) = x³ + 3x² + 20x + k = 0
p ( - 3 ) = ( - 3 ) ³ + 3 × ( - 3 ) ² + 20 × ( - 3 ) + k = 0
- 27 + 27 - 60 + k = 0
k = 60
Hope it helps
x = - 3
p ( x ) = x³ + 3x² + 20x + k = 0
p ( - 3 ) = ( - 3 ) ³ + 3 × ( - 3 ) ² + 20 × ( - 3 ) + k = 0
- 27 + 27 - 60 + k = 0
k = 60
Hope it helps
Oh I confused in signs
any problems in my answer??
no
okay :-)
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