If mLAPB=
50° then find
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Answer:
∠ACB=50
o
,∠ACB=∠CAD(∵BC∣∣AD)
In △AOD,∠DAO+∠ADO+∠AOD=180
o
50+∠ADB+90
o
=180
o
∠ADB=180
o
−140
o
=40
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