Question

If mode of a series exceeds its mean by 12 then the mode exceeds the median by

Answer 1

Suppose mean be x
So, mode will be x + 12
Then 3 median will be:
= x + 12+ 2x
= 3x + 12
or 3 (x+4)

So, 1 median or median will be:

(x+4)

Here, Mode - Median 
= (x+12) - (x+4)
= x + 12 - x + 4
= 8

∴ The mode exceeds the median by 8.

Answer 2

Given:
Let assume mean as X
Mode exceeds mean by 12
so, Mode=X+ 12 ------(equation 1)
By using Empherical relation :
*************************************
3Median= Mode + 2 Mean
*************************************
3Median = X + 12+ 2X
3Median =3X + 12
3Median=3(X +4)
Median=X + 4-----(equation 2)
equation (1) - equation (2)
Mode - Median =X + 12 -(X+4)
Mode - Median=12-4
Mode - Median= 8
Hence Mode exceeds Median by 8