Question

if Mohan gives an interes of Rs.81 for one year at 9% rate per annum. What is the sum he has borrowed?

Answer 1

Step-by-step explanation:

P=?

T=1YEAR

R=9%

SI=81/-

SI=PTR/100

81=P×1×9/100

P=SI×100/T×R

P=81×100/1×9

P=900/-

THE SUM HE HAS BORROWED IS 900/-

Answer 2

$s.i. = > \: \frac{p \times r \times t}{100}$

$81 = \frac{p \times 1 \times 9}{100}$

$p = 900$