if Mohit drives a bike at a rate of 24 km/hr, he reaches his destination 5 minutes late. if he drives at a rate of 30km/hr , he reaches his destination 4 minutes too soon . how far his destination.
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Assume that he starts travelling to his workplace at the same time every day
Let the distance between his work place and home be 'd'
Let the actual time be 'x'
Distance = Speed * Time
Convert minutes into seconds as the units should be in kmph
As 24 kmph speed resulted in 5 minutes late, it is taken as increment
d = 24(x + 5/60) ---------------(1)
As 30 kmph speed resulted in 4 minutes early, it is taken as decrement
d = 30(x - 4/60) ----------------(2)
(1) and (2) are equal
=> 24(x + 5/60) = 30(x - 4/60)
=> 24x+2 = 30x-2
=> 30x - 24x = 2+2
=> 6x = 4
=> x = 2/3
Substitute the value of x in (1)
=> d = 24(2/3 + 5/60)
=> d = 24(9/12)
=> d = 18 km
The required answer is 18 km
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