Question

if molality of aqueous solution of glucose is 0.2 then mole fraction of solvent in this solution is?

Answer 1

Mole fraction of solute is related to molality by the following equation:  

$X_{a}=\frac{(m\times MM(Solvent)}{(1000+m\times MM(Solvent)}$

Where, m is the molality  

MM(Solvent) is the molar mass of the solvent  

X is the mole fraction of the solute  

MM(water) is 18 g mol  

X is the mole fraction of the glucose is needs to be find

Putting the values in the equation,  

$X=\frac{(0.2\times18)}{(1000+0.2\times 18)}$

So, mole fraction of solute that is glucose is 0.0036

Mole fraction of solvent is 1-0.0036=0.9964

Answer 2

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☆ Molality (m) is defined as the number of moles of solute per kilogram of solvent.

☆ Molarity is a measurement of the moles in the total volume of the solution, whereas molality is a measurement of the moles in relationship to the mass of the solvent.