If molality of urea solution is 2m. Find out its mole fraction in aq sol4.
Answers
Answer:
➡ GIVEN :- mole fraction of urea in the given aqueous solution is 0.02.
MOLE FRACTION OF WATER WILL BE :-
= 1 - mole fraction of urea
= 1 - 0.02
= 0.98
Thus, no. of moles of urea in the solution will be = mole fraction of urea in solution X total number of moles of the solution
= 0.02 X 1 = 0.02
Similarly, the number of moles of water in the solution will be = mole fraction of water in solution X total number of moles of the solution
= 0.98 X 1
= 0.98
So, mass of urea present in solution will be = number of moles of urea X molar mass of urea
= 0.02 X 60
= 1.2g
Similarly mass of water present in the solution will be = number of moles of water X molar mass of water
= 0.98 X 18 = 17.64g
Now, molality of a solution is given by the following relation
molality = number of moles of solute / Mass of solvent (in Kg)
So, molality of urea solution will be = 0.02 / 0.0176
= 1.136 m
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