if mole fraction of Naoh in its aqueous solution is 0.2 ,then approximate molality of Naoh solution will be
A.13.9
b.10.9
Answers
Answered by
86
Definition:
Molality is the moles of solute per Kg of the solvent.
In this case the solvent is water.
Moles in 1000g of water is :
1000 / 18 = 55.6moles
Mole fraction of solute = moles of solute / total moles
Let moles of a NaOH be X then :
X / (X + 55.6) = 0.2
X = 11.12 + 0.2X
0.8 X = 11.12
X = 11.12 / 0.8
X = 13.9
The molality of NaOH is thus 13.9
Molality is the moles of solute per Kg of the solvent.
In this case the solvent is water.
Moles in 1000g of water is :
1000 / 18 = 55.6moles
Mole fraction of solute = moles of solute / total moles
Let moles of a NaOH be X then :
X / (X + 55.6) = 0.2
X = 11.12 + 0.2X
0.8 X = 11.12
X = 11.12 / 0.8
X = 13.9
The molality of NaOH is thus 13.9
Answered by
1
Answer:
13.9
Explanation:
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