if mole fraction of water in aqueous solution of cacl2 is 0.9 what is the mass of solution???? ( molar mass of cacl2 is 111)
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As per the formula
X1+X2= 1
Here X1 represents mole fraction of solvent and X2 represents mole fraction of solute
X1 =0.9 then X2=0.1
If mass of water is 100g and molar mass is 18
Moles 1=100/18=5.55
X1=moles 1/total moles
Total moles = 5.55/0.9=6.17
X2= moles 2/ total moles
Moles 2=0.1×6.17=0.617
Moles 2= weight /molar mass
Weight=0.617×111=68.5g
I hope this helps ( ╹▽╹ )
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Answer:
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