Question

If moments of a particle is p = ( 2t³ - 3t² + 3t + 1 ) kgm/s. Find force at t = 2 sec ??​

Answer 1

Explanation:

Aloha. !

$\text { This is Sweety Adihya }$

p = ( 2t³ - 3t² + 3t + 1 )

Diff w.r.t to 't',.

dp/dt= 4t²-9t+3

At t=2 sec

dp/dt=4(2)²-9(2)+3

dp/dt=4×4-18+3

dp/dt= 16-18+3

dp/dt=1

Hope it will help you

@ Sweety Adihya

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Answer 2

Answer:

Hey mate ✌✌

➡️ F = dp/dt = d/dt ( 2t³-3t²+3t+1 )

➡️ F = 6t² - 6t + 3.

At t = 2 sec,

➡️ F = 6(2)² - 6(2) + 3

➡️ F = 24 - 12 + 3

➡️ F = 15 N ans.

Explanation: