Question

if momentum decreases by 20% k. e. will decrease by?

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Answer 1

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Answer 2

KE = p^2/2m

Momentum decreases by 20%
So p' = 0.8p

KE' = p'^2/2m

KE' = (0.8p)^2/2m

KE' = 0.64 p^2/2m

KE' = 0.64 KE

Decrease in KE = (1-0.64)KE = 0.36

% decrease in KE = 36%

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