Question

if momentum increase by 13% then kE increase by %?​

Answer 1

Answer:

if momentum increase by 13% then kE increase by 39%

Answer 2

Given that momentum is increased by  13%.  

We have to find how much the kinetic energy will increase

As we know the relation between kinetic energy and momentum is given by:

$K=\frac{P^{2}}{2m}$     (where K = Kinetic Energy

                             P = momentum

                             m = mass )

Now, if the mass remains constant, then kinetic energy is equal to the square of momentum i.e. $K\alpha P^{2}$

Hence the change in kinetic energy will be equal to twice the change in momentum.

⇒ ΔK/K=2ΔP/P

   ΔK/K=$2*13$

   ΔK/K=$26$%

∴ Change in the kinetic energy is equal to 26% when there is a change in 13% of the momentum.