if momentum increases by 10% then increase in kinetic energy will be ? explain it
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k.e=p²/2m
when change occurs
ke becomes (11p/10)²/2m
121p²/200m
so increase in k.e=121p²/200m-p²/2m
=(121p²-100p²)/200m
=21p²/200m
or increase percentage=(21p²/200m÷p²/2)*100
=21%
when change occurs
ke becomes (11p/10)²/2m
121p²/200m
so increase in k.e=121p²/200m-p²/2m
=(121p²-100p²)/200m
=21p²/200m
or increase percentage=(21p²/200m÷p²/2)*100
=21%
Anonymous:
hey champ understood.or not???
noo
dont know from where tht 11 121 comes ?
oh
i squared it
can u write it on the page n then send it
so when velocity increases then it becomes 11/10 of the initial
sorry no resources available now
hmm
bye happy holi
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