Question

if momentum is increased by 10% than increase in K.E will be??​

Answer 1

Answer:

It will be increased by 21%

Let the initial mass of the body be m and its velocity be v. 

Initial momentum of the body = mv 

Initial KE = mv^2/2 

If the momentum increases by 10%, new momentum = mv + 10% of mv 

= mv + 10/100mv 

= mv + mv/10 

=11mv/10 

=m(11v/10) 

New velocity = 11v/10 

Increase in velocity = v/10 

New KE = m(11v/10)^2/2 

= 121/100mv^2/2 

Increase in KE = 21%

Answer 2

Answer:

Explanation:

K = 1/2 * mv^2 = p^2/2m so,

K ∝ p^2

Ki/Kf = Pi^2/(1.1)^2*Pi^2 = 1/1.21 ,,

Kf = 0.82864Ki

Kf% = 82.8%Ki