Question

If momentum is increased by 20% then K.E increases by? plz explain plzzzzz

Answer 1

Hi Mate!!!

K.E = p² / 2m

{( K.E )f -( K.E )I/ K.E)I. } ×100 =. ( pf² - pi² / pi² ) ×100

Pf= 100+20. pi = 100.


Change in K.E = ( 120)² - (100)

Answer 2

may be it will help u