Question

If momentum of a body is doubled the k'e becomes with solution

Answer 1

this will be the answer,

k'e=

Answer 2

momentum p=mv

if it is doubled p=2mv

p=m(2v)

kinetic energy K.E=(1/2)×m(2v)^2

K.E=4×(1/2×mv^2)

so, kinetic energy changes 4times the original