Question

If momentum of an object is doubled, then what is the change in its kinetic energy?

Answer 1

let's initial momentum is P and initial kinetic energy is K,

and final kinetic energy is K' ........

then ,

K=P^2 / 2m......................(1)

K' = (2P)^2 / 2m...................(2)

if equation (2) is divided by equation (1),

K'/K=(2P/P)^2

K'/K= 4

on cross multiplication,

K'=4K

I hope this will help you