If momentum of an object is increased by 10 %, then its kinetic energy will increase by
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Now, we know K.E.= p²/2m (original K.E.)
Now, if Momentum (p) is increased by 10%, new momentum=110p/100
∴ putting new momentum: K.E= (11p/10)²/2m
⇒K.E.= (121p²/100)/2m (new K.E.)
∴ Change in K.E. %:
(difference between new and original K.E./ Original K.E.) · 100
⇒ {{[(121p²/100)/2m] - [p²/2m]} /(p²/2m) } · 100
⇒ [(21p²/200m)/(p²/2m)] · 100
⇒ (21/100) · 100
⇒ 21%
∴There is an increase of 21% in Kinetic Energy if momentum is increased by 10%
Now, if Momentum (p) is increased by 10%, new momentum=110p/100
∴ putting new momentum: K.E= (11p/10)²/2m
⇒K.E.= (121p²/100)/2m (new K.E.)
∴ Change in K.E. %:
(difference between new and original K.E./ Original K.E.) · 100
⇒ {{[(121p²/100)/2m] - [p²/2m]} /(p²/2m) } · 100
⇒ [(21p²/200m)/(p²/2m)] · 100
⇒ (21/100) · 100
⇒ 21%
∴There is an increase of 21% in Kinetic Energy if momentum is increased by 10%
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