Question

if Momentum p and velocity V are related as P is equals to root a upon B + v square then the dimensional formula of area ab-2 is​

Answer 1

Answer:

The dimension formula of ab⁻² is $[M^2LT^{-3}]$.

Explanation:

Given that,

Momentum = p

Velocity = v

Relation between momentum and velocity

$P=\dfrac{\sqrt{a}}{b}+v^2$

On squaring both side

$P^2=ab^{-2}+v$

$P^2-v=ab^{-2}$....{I}

The dimension formula of P and v

$P=[MLT^{-1}]$

$v=[LT^{-1}]$

Now, put the dimension formula in equation (I)

$ab^{-2}=([MLT^{-1}])^2-[LT^{-1}]$

$ab^{-2}=[M^2LT^{-3}]$

Hence, The dimension formula of ab⁻² is $[M^2LT^{-3}]$.

Answer 2

Explanation:

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