Question

If momentum (P ), area (A) and time (T ) are taken to be fundamental quantities, then energy has the dimensional formula
(a) (P^1 A^–1 T^1)
(b) (P^2 A^1 T^1)
(c) (P^1 A^–1/2 T^1)
(d) (P^1 A^1/2 T^–1)

Answer 1

Answer:
           d ) (P^1 A^1/2 T^–1)
 Explanation :
   We know that ,
               Dimensions of Energy = ML^2T^-2 ------------ (1st)
             MOmentum = MLT-1 or P = MLT-1 where (P is momentum) -------- (a)
             Area = L^2  or A^1/2 = L ---------(b) (where A is area)
Using a,b in 1st , we get
             Dimensions of Energy =  P ^1 A^1/2T^-1

Answer 2

Answer:

Explanation:

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