if momentum=sin omega ti^ + cos omega tj^, and force = cos omega t (omega) i^ - sin omega t (omega) j^, what is the angle between them?
maribmushtaq:
hey anybody answer
Answers
Answered by
1
take dot product.
if don't know then I can Google, it's a simple topic.
(sin wt i^+cos wt j^).(wcos wt i^-wsin wt j^)
= w sin(wt)cos(wt) - wcos(wt)sin(wt)
=0
so
0=|P||F|cos theta
cos theta =0
theta = 90°.
: )
if don't know then I can Google, it's a simple topic.
(sin wt i^+cos wt j^).(wcos wt i^-wsin wt j^)
= w sin(wt)cos(wt) - wcos(wt)sin(wt)
=0
so
0=|P||F|cos theta
cos theta =0
theta = 90°.
: )
Similar questions