Math, asked by ItzAkshuSai692245, 3 months ago

if motu and patalu starts a business by investing rs 10000 and Rs20000 respectively and revice the profit of 6000at the end of year then share of profits for each partner of respectily​

Answers

Answered by Aloneboi26
4

Step-by-step explanation:

Carbon dioxide is a colorless gas with a density about 53% higher than that of dry air. Carbon dioxide molecules consist of a carbon atom covalently double bonded to two oxygen atoms. It occurs naturally in Earth's atmosphere as a trace gas

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Motu's share of profit is Rs. 2,000

Motu's share of profit is Rs. 2,000Patalu's share of profit is Rs. 4,000

Explanation:-

Given :

Money invested for starting the business by Motu = Rs 10,000

Patalu invested money = Rs 20,000

Profit received at the end of the year = Rs 6,000

To find :

Share of profits for each partner of respectively

Solution :-

Motu's Share = 10,000 × 12

⇒ 1,20,000

Patalu's Share = 20,000 × 12

⇒ 2,40,000

⇒ 12 : 24

★ Motu's Share : Patalu's Share

⇒ 1 : 2

★ Total Profit = Rs 6,000

Motu's Share =31×6,000

Patalu's Share =2 3x 6,000

⇒ 4,000

Therefore,

Motu's share of profit is Rs. 2,000

Patalu's share of profit is Rs. 4,000

_________❤__________

Answered by llMissSwagll
28

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Motu's share of profit is Rs. 2,000

Patalu's share of profit is Rs. 4,000

Explanation:-

Given :

Money invested for starting the business by Motu = Rs 10,000

Patalu invested money = Rs 20,000

Profit received at the end of the year = Rs 6,000

To find :

Share of profits for each partner of respectively

Solution :

Motu's Share = 10,000 × 12

⇒ 1,20,000

Patalu's Share = 20,000 × 12

⇒ 2,40,000

⇒ 12 : 24

★ Motu's Share : Patalu's Share

⇒ 1 : 2

★ Total Profit = Rs 6,000

Motu's Share = \tt{\dfrac{1}{3} \: \times \: 6,000}31×6,000

⇒ 2,000

Patalu's Share = \tt{\dfrac{2}{3} \times 6,000}32×6,000</p><p>

⇒ 4,000

Therefore,

Motu's share of profit is Rs. 2,000

Patalu's share of profit is Rs. 4,000

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