Question

if movement of inertia of a sphere is 2/5MR² through an axis passing through the centre then along the tangent will be?
${\blue{\bold{\text{ExPlAnAtIoN NeEdEd}}}}$​

Answer 1

${\mathcal{\purple}{h} \green{e} \red{ll} \pink{o}}$

$\bf\underbrace \red{your \: question's \: answer}$

The moment of inertia (M.I.) of a sphere about its diameter

$= \frac{2 MR²}{5}$

According to the theorem of parallel a

xes, the moment of inertia of a body about any axis is equal to the sum of the moment of inertia of the body about a parallel axis passing through its centre of mass and the product of its mass and the square of the distance between the two parallel axes.

The M.I. about a tangent of the sphere

$= \frac{2{MR}^{2}+MR 2}{5}$

$= \frac{7{MR}^{2}}{5}$

Hence! Proved