If mth term of a hp is n and nth term is m then (m+n)th term is
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23
In the attachments I have answered this problem.
Concept:
The n th term of HP is
T(n) = 1 /[a+(n-1)d]
See the attachment for detailed solution
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Answered by
16
Answer:
Given that,m
th
term of an H.P. is n and n
th
term is m.
Therefore, m
th
term of an A.P. is
n
1
and n
th
term is
m
1
.
Let, a be the first term and d be the common difference of the A.P
Now, t
m
=a+(m−1)d=
n
1
....(1)
And t
n
=a+(n−1)d=
m
1
....(2)
Subtracting (1) & (2), we get
(m−n)d=
n
1
−
m
1
⇒d=
mn
1
Substituting d in (1), we get
a+
mn
(m−1)
=
n
1
⇒a=
mn
1
Therefore, t
mn
=a+(mn−1)d=
mn
1
+
mn
(mn−1)
=1
and thus mn
th
term of H.P is 1.
Step-by-step explanation:
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