Question

If mth term of an AP is n and nth term is m then prove that (m+n) is 0.

Answer 1

here is your answer which you want

Answer 2

Answer:

Step-by-step explanation:

Mterm=a+(m-1)d=n

Nth term =a+(n-1)d=m

Mam=Nan

M[a+(m-1)d]=n[a+(n-1)d]

Bring nth term on other side then

A(m-n)+{m(m-1)-n(n-1)}d=0

A(m-n)+{(msq-nsq)-(m-n)}d=0

(M-n){a+(m+n-1)d}=0

A+(m+n-1)=0

Am+n=0

Hence proved.