Question

if mx^2+4x+2=0 has real roots,find the largest possible value of m

Answer 1

Answer:

The largest possible value will be 2.

Answer 2

Answer:

m=2

Since real roots can only be formed when the discriminant is 0, therefore,       D=0,

D=b^2 -4ac , a=m, b=4, c=2, putting these values in the equation we will get,   0=4^2-4(m)(2)                                                                                                         0=16-8m

8m=16

m=16/8

m=2