Math, asked by superdhanraj21, 10 months ago

If mx^2 < nx such that m and n have opposite signs then x can be (m being positive)

(a) x > n/m

(b) x < n/m

(c)n/ m < x < 0

(d) None of these

Answers

Answered by awantikapundir
3

Answer:

your ans B

I hope it help

Answered by Anonymous
2

Answer:

THE ANSWER IS OPTION B) x < n/m.

Step-by-step explanation:

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