If mx+ny= m²-n² and ny + mx = 0, find the value of (x+y)
[The value of (x+y) is 'm-n ' but i don't know how. please help in this]
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mx + ny = m²-n² ................ ( 1 )
mx + my = 0 .................( 2 )
multiplying n with equation ( 1 ) & m with equation ( 2 ) ,
mnx + n² y = m²n - n³ ............ ( 1 )
mnx + m² y = 0 ............... ( 2 )
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( n²- m²) y = n ( m²- n² )
y = - n
put y = - n in equation ( 1 )
mx - n² = m²- n²
x = m
so , ( x + y ) = m - n
Hence , value of ( x + y ) is ( m - n )
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