Question

If mx+ny= m²-n² and ny + mx = 0, find the value of (x+y)

[The value of (x+y) is 'm-n ' but i don't know how. please help in this]

Don't type useless things just to gain points plz otherwise I'm gonna report you people​

Answer 1

Answer:

Hlo mate i think in second eq it is. nx+my.= 0 Right

$mx + ny = {m}^{2} - {n}^{2} ...................(1) \\ \\ nx+ my = 0.............................(2) \\ \\ add \: \: both \: \: the \: equation. \\ \\ (mx + ny) + (nx + my) = {m }^{2} - {n}^{2} \\ \\ (mx + my) + (nx + ny) = {m}^{2} - {n}^{2} \\ \\ m(x + y) + n(x + y) = {m}^{2} - {n}^{2} \\ \\ (x + y)(m + n) = {m}^{2} - {n}^{2} \\ \\ (x + y) = \frac{( {m}^{2} - {n}^{2} ) }{(m + n)} \\ \\ x + y = \frac{(m + n)(m - n)}{m + n} \\ \\ x + y = \: m - n$

Answer 2

Answer:

I am answering just bcz you can male the upper ans as brainlest