If mx²+nx²+x-6 has (x+2) as a factor and leaves a remainder4 when divided by (x-2) find the value of m and n
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Step-by-step explanation:
Let p(x)=x
3
+mx
2
−x+6 as (x−2) is a factor of p(x)
⇒p(2)=0⇒8+4m−2+6=0⇒4m=−12⇒m=−3
x−3)x
3
−3x
2
−x+6(x
2
−1
x
3
−3x
2
−x+6
+x+3
3=n
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