Math, asked by vanshikhaasnani, 21 days ago

If mx²+nx²+x-6 has (x+2) as a factor and leaves a remainder4 when divided by (x-2) find the value of m and n​

Answers

Answered by sipraacharjer
0

Step-by-step explanation:

Let p(x)=x

3

+mx

2

−x+6 as (x−2) is a factor of p(x)

⇒p(2)=0⇒8+4m−2+6=0⇒4m=−12⇒m=−3

x−3)x

3

−3x

2

−x+6(x

2

−1

x

3

−3x

2

−x+6

+x+3

3=n

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