Math, asked by kiarasn, 11 months ago

if n = 1+2 root 2 then evaluate n^2 +1/ n^2​

Answers

Answered by Anonymous
1

\huge{\sf{\boxed{\red{Answer:-}}}}

given:-

n=1+2 \sqrt{2}

=\large{\frac{n^2+1}{n^2}}

=\large{\frac{(1+2√2)^2+1}{(1+2√2)^2</p><p>}}

=\large{\frac{1^2+2(2√2)(1)+(2√2)^2+1}{1^2+2(2√2)(1)+(2√2)^2}}

=\large{\frac{1+4√2+8+1}{1+4√2+8}}

=\large{\frac{10+4√2}{9+4√2}}

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