if n=1/4andy=3/2then value of(n+y)÷(n-y)
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n = 1/4 and y = 3/2
n+y = 1/4 + 3/2
= (1+6)/4
= 7/4
n-y = 1/4 - 3/2
= (1-6)/4
= (-5/4)
(n+y)/(n-y) = (7/4) ÷ (-5/4)
= 7/4 × 4/-5
= 7/-5 = -7/5
n+y = 1/4 + 3/2
= (1+6)/4
= 7/4
n-y = 1/4 - 3/2
= (1-6)/4
= (-5/4)
(n+y)/(n-y) = (7/4) ÷ (-5/4)
= 7/4 × 4/-5
= 7/-5 = -7/5
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Step-by-step explanation:
n=1/4andy=3/2then value of(n+y)÷(n-y)
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