Question

if ( n-1 ) is a factor of 4n³+3n²–4n+k. then find the value of k.​

Answer 1

Given:

• 4n³ + 3n² - 4n + k

Find:

• Value of K

Solution:

▢ (n - 1) = n = 1

↬ 4 ༝ (1)³ + 3 ༝ (1)² - 4 ༝ 1 + k

↬ 4 + 3 - 4 + k

↬ 3 + k

↬ k = -3

• Hence, the value of k is -3.

Answer 2

4n³ + 3n² - 4n + k

12n² + 6n - 4