if n 10 summation of x= 150 summation of y =260 summation of xy = 2640 then cov(x,y) is
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1 2 12 is a root of quadratic equation. ∴ ∴ It must satisfy the quadratic equation. x2 + kx - 5 4 54 = 0 ( 1 2 ) 2 (12)2 + k ( 1 2 ) (12)- 5 4 54 = 0 ⇒ ⇒ 1 4 14 + k 2 k2- 5 4 54 = 0 1 + 2 k − 5 4 1+2k−54 = 0 ⇒ ⇒ 2k - 4 = 0 ⇒ ⇒ k = 2Read more on Sarthaks.com - https://www.sarthaks.com/28375/if-1-2-is-a-root-of-the-equation-x-2-kx-5-4-0-then-find-the-value-of-k
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