If n(μ)=100, n(A)=50, n(B)=20 and n(A
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n(U)=50,n(A)=20
n(A∪B)=18 n(B−A)=?
So, n(A∪B)=n(0)−n(A∪B)
So. n(A∪B)=32
n(B−A)=n(A∪B)−n(A)
=32−20
n(B−A)=12
Step-by-step explanation:
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