If n(μ) = 100, n(A) = 50, n(B) = 20 and n(AnB)=10, then a[(AUB^c] = (plz answer fast online exam)
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n(U)=50,n(A)=20
n(A∪B)=18 n(B−A)=?
So, n(A∪B)=n(0)−n(A∪B)
So. n(A∪B)=32
n(B−A)=n(A∪B)−n(A)
=32−20
n(B−A)=12
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