If n(ξ) = 120, n(A’) = 60,n(B) = 70, and n(AՈB) = 20find n((AUB)’)
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Solution :
n(A) – n(AUB)
n(A) – n(A⋂B)
n(B) – n(A⋂B)
n( ξ) – n(AUB) where ξ means Universal Set
n(A) – n(AUB)
n(A) – n(A⋂B)
n(B) – n(A⋂B)
n( ξ) – n(AUB) where ξ means Universal Set
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