Math, asked by jangra4576, 19 days ago

If n=2^2 x 3^3 x 5^4 x 7, then number of consecutive zeroes in n, where n is a natural number is :
(a) 2
(b) 3
(c) 4
(d) 7​

Answers

Answered by khrisha08
0

Answer:

(a) 2

Step-by-step explanation:

2^2 x 3^3 x 5^4 x 7 = 472500

so it is 2

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