Question

If n=2^3*3^4*4^4*7 then the number of consecuitive zeros in n where n is a natural number

Answer 1

Answer:

n=2^3* 3^4* 7*15^6

=2^3* 3^4* 7* 3^6* 5^6

we get 0 when we a 2 with a 5

so there are three 2s ,six 5s and

hence we get 3 consecutive zeros in the value of n

hope it helps

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