Math, asked by manaswinidomakondama, 2 months ago

if n=2'3×3'4×5'4×7 then find the number of consecutive zeroes in n where n is natural number​

Answers

Answered by rounitmourya2001
0

Answer:

n = 23 x 34 x 54 x 7

n x 53 x 5 x 7 = 23 x 34 x

n = (2x 5)³ x 34 x5x7

n = (10)3 x 34 x 5x7

n = 34 x 5 x 7 x 1000

Thus, in the given natural number 'n' there are 3

zeros.

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