if n=2'3×3'4×5'4×7 then find the number of consecutive zeroes in n where n is natural number
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Answer:
n = 23 x 34 x 54 x 7
n x 53 x 5 x 7 = 23 x 34 x
n = (2x 5)³ x 34 x5x7
n = (10)3 x 34 x 5x7
n = 34 x 5 x 7 x 1000
Thus, in the given natural number 'n' there are 3
zeros.
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