if n = 2*3 × 3*4 × 5*4 × 7 then the number of consecutive zeros is 'n' where n is a natural number us?
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2^3=8
3^4=81
5^4=625
2^3×3^4×5^4×7
=8×81×625×7
=2835000
there fore n= 3
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