Question

if n= 2^4 × 3^4 × 5^2 ×7 then find the number of zeroes in n​

Answer 1

Answer:

If any number ends with the digit 0, it should be divisible by 10, i.e. it will be divisible by 2 and 5. Prime factorization of n is given as 23 × 34 × 54 × 7. It can be observed that there is (2 × 5) × (2 × 5) × (2 × 5) ⇒ 10 × 10 × 10 = 1000 Thus, there are 3 zeros in n.Read more on Sarthaks.com - https://www.sarthaks.com/1074190/if-n-2-3-3-4-5-4-7-then-the-number-of-consecutive-zeros-in-n-where-n-is-a-natural-number-is-a-2-b-3

Step-by-step explanation:

PLEASE MARK ME AS THE BRAINLIEST !!!

PLEASE UNDERSTAND MY FEELINGS!!!

PLEASE FOLLOW ME!!!