If n-2,4n-1,5n+2 are in a. p find n?
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Answered by
2
ap=n-2,4n-1,5n+2
a=n-2
d=(4n-1)-(n-1)
=(4n-1)-n+1
=-4n^2+n+4n-1
=4n^2-5n+1
=4n^2-4n-n+1
=4n(n-1)-1(n-1)
n=1/4 n=1
a=n-2
d=(4n-1)-(n-1)
=(4n-1)-n+1
=-4n^2+n+4n-1
=4n^2-5n+1
=4n^2-4n-n+1
=4n(n-1)-1(n-1)
n=1/4 n=1
Answered by
2
ap=n-2,4n-1,5n+2
a=n-2
d=(4n-1)-(n-1)
=(4n-1)-n+1
=-4n^2+n+4n-1
=4n^2-5n+1
=4n^2-4n-n+1
=4n(n-1)-1(n-1)
n=1/4 n=1
hope it helps!!
a=n-2
d=(4n-1)-(n-1)
=(4n-1)-n+1
=-4n^2+n+4n-1
=4n^2-5n+1
=4n^2-4n-n+1
=4n(n-1)-1(n-1)
n=1/4 n=1
hope it helps!!
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