If n-2, 4n-1a nd5n+2 are in a.p, then find the value of n
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Answer:
we know that ,
if a,b, c, are in ap
then,
2b = a+ c
so,
2( 4n - 1) = n - 2 + 5n + 2
=> 8n - 2 = 6n
=> 8n - 6n = 2
=> 2n = 2
=> n = 2/2
=> n = 1
so,
the value of n is 1.
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